0=28x-35-7x^2

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Solution for 0=28x-35-7x^2 equation: 



0=28x-35-7x^2

We move all terms to the left:

0-(28x-35-7x^2)=0

We add all the numbers together, and all the variables

-(28x-35-7x^2)=0

We get rid of parentheses

7x^2-28x+35=0

a = 7; b = -28; c = +35;
Δ = b2-4ac
Δ = -282-4·7·35
Δ = -196
Delta is less than zero, so there is no solution for the equation

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